loxcorp
Rank #123,457glama/loxcorp/loxdev
Provides live, read-only access to Robinhood Chain and Lox Corp data, enabling AI agents to query chain stats, token launches, agent details, and more.
loxcorp is a Model Context Protocol (MCP) server published by loxcorp. It ranks #123,457 of 137,138 servers tracked on MCP Toplist. loxcorp is listed on Glama, and ships as a single rolling release with no explicit version metadata. It was first listed on Jul 28, 2026.
Ranks ahead of 13,681 of 137,138 servers on MCP Toplist.
Use loxcorp
No credentials or required configuration declared — add it to your MCP client and go.
This server doesn't publish a machine-readable install config — see the repository README for install instructions.
Show your rank
Maintain this server? Add the live rank badge to your README — it updates automatically as the leaderboard changes.
[](https://mcptoplist.com/server/glama%2Floxcorp%2Floxdev)<a href="https://mcptoplist.com/server/glama%2Floxcorp%2Floxdev"><img src="https://mcptoplist.com/badge/glama%2Floxcorp%2Floxdev.svg" alt="MCP Toplist: #123,457 of 137,138" /></a>Variants: append ?metric=score or ?metric=stars to the image URL.
Listed on 1 registry
loxcorp
Not versioned
This server is published through a registry that does not expose explicit version metadata, and no GitHub release tags were found on the linked repository. The listing tracks a single rolling release.
Frequently asked questions
- Who maintains loxcorp?
- loxcorp is maintained by loxcorp, which publishes 1 MCP server (0 total versions) tracked on MCP Toplist.
- Is loxcorp listed on the Official MCP Registry?
- loxcorp is not on the Official MCP Registry. It is listed on Glama.
- How many versions does loxcorp have?
- loxcorp ships as a single rolling release with no explicit version metadata.
- Where can I find the source code for loxcorp?
- The source code for loxcorp is hosted at github.com/loxcorp/loxdev.
Do you run this server?
Community projects list the MCP servers behind real agents and apps. Publish yours and this page will link to it.